According to multiple sources — first reported by Adrian Wojnarowski of Yahoo! Sports — free agent small forward Andre Iguodala has signed a four-year, $48 million dollar contract to play for the Golden State Warriors.
Iguodala to the Warriors began to pick up a lot of steam as sources earlier today reported that Golden State was Iguodala’s top choice. Minutes before the signing of Iguodala was announced, it was reported that Golden State had traded the combined $24 million of Andris Biedrins, Brandon Rush, and Richard Jefferson to the Utah Jazz. Details on the trade are still to come.
There is still a lot that has to be played out. As far as the Dwight Howard sweepstakes go, the Warriors still got a shot, but it will most definitely require finding a new home for Andrew Bogut and even possibly David Lee, depending on whether both Klay Thompson and Harrison Barnes remain with the team.
There could still be a sign-and-trade with the Lakers, sending away Bogut and either Thompson or Barnes. Or Golden State may be able to clear enough space to sign Howard outright, but that would take a lot of work.
The Warriors could just stand pat, have a starting five of Curry, Thompson, Iguodala, Lee and Bogut with Harrison Barnes off the bench.
But it seems like they are going for the grand slam and put together the super team of Curry-Iguodala-Howard.